题目¶
原题地址:https://leetcode.com/problems/maximum-depth-of-binary-tree/
Given the root of a binary tree, return its maximum depth.
A binary tree's maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
Example 1:
Input: root = [3,9,20,null,null,15,7] Output: 3
Example 2:
Input: root = [1,null,2] Output: 2
Example 3:
Input: root = [] Output: 0
Example 4:
Input: root = [0] Output: 1
Constraints:
- The number of nodes in the tree is in the range [0, 104].
- -100 <= Node.val <= 100
解法¶
求左右子树各自的最大深度,然后进行比较取最大值再加一,即为 root 节点的最大深度。
这个方法的 Python 代码类似下面这样:
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def maxDepth(self, root):
if root is None:
return 0
return 1 + max(self.maxDepth(root.left), self.maxDepth(root.right))
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