题目¶
原题地址:https://leetcode.com/problems/path-sum/
Given the root of a binary tree and an integer targetSum, return true if the tree has a root-to-leaf path such that adding up all the values along the path equals targetSum.
A leaf is a node with no children.
Example 1:
Input: root = [5,4,8,11,null,13,4,7,2,null,null,null,1], targetSum = 22 Output: true
Example 2:
Input: root = [1,2,3], targetSum = 5 Output: false
Example 3:
Input: root = [1,2], targetSum = 0 Output: false
Constraints:
- The number of nodes in the tree is in the range [0, 5000].
- -1000 <= Node.val <= 1000
- -1000 <= targetSum <= 1000
解法¶
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution(object):
def hasPathSum(self, root, targetSum):
if root is None:
return False
if root.left is None and root.right is None and root.val == targetSum:
return True
new_sum = targetSum - root.val
return self.hasPathSum(root.left, new_sum) or self.hasPathSum(root.right, new_sum)
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