题目¶
原题地址:https://leetcode.com/problems/n-ary-tree-level-order-traversal/
Given an n-ary tree, return the level order traversal of its nodes' values.
Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).
Example 1:
Input: root = [1,null,3,2,4,null,5,6] Output: [[1],[3,2,4],[5,6]]
Example 2:
Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] Output: [[1],[2,3,4,5],[6,7,8,9,10],[11,12,13],[14]]
Constraints:
- The height of the n-ary tree is less than or equal to 1000
- The total number of nodes is between [0, 10^4]
解法¶
广度优先,从上到下一层一层遍历,保存每一层的 value。
这个方法的 Python 代码类似下面这样:
"""
# Definition for a Node.
class Node(object):
def __init__(self, val=None, children=None):
self.val = val
self.children = children
"""
class Solution(object):
def levelOrder(self, root):
if root is None:
return []
values = []
children = [root]
while children:
children_values = []
new_children = []
for c in children:
children_values.append(c.val)
if c.children:
new_children.extend(c.children)
values.append(children_values)
children = new_children
return values
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